Bisolvon ovo ne može biti rješenje jer x2=400 > 350 suprotno ograničenju
anon00 rješenje je (x1, x2) = (1800, 350), potvrđeno sa scipy.linprog.optimize
>>> from scipy.optimize import linprog
>>> c = [-7, -50]
>>> A = [ [1, 0], [0,1], [-1, 4], [3,4]]
>>> b = [2000, 350, 400, 6800]
>>> linprog(c, A, b, method='simplex')
con: array([], dtype=float64)
fun: -30100.0
message: 'Optimization terminated successfully.'
nit: 5
slack: array([200., 0., 800., 0.])
status: 0
success: True
x: array([1800., 350.])
